The Joint Entrance Examination is a national level engineering entrance examination which is conducted for candidates seeking admission to the topmost engineering institutes such as IITs, NITs, and CFTIs etc. All of us know that from this year, JEE Main will be conducted by the National Testing Agency (NTA) twice a year. The JEE Main Admit Card 2019 has been released by the NTA on its official website.
NTA has also announced the exam pattern of JEE Main 2019 on its official website. Keep reading the article to know the complete details about the JEE Main 2019 exam pattern and marking scheme.
JEE Main 2019 Exam Pattern and Marking Scheme
According to the JEE Main exam pattern 2019, the entrance examination comprises two papers namely Paper I and Paper II. Paper I is conducted for admission to B.Tech programs and Paper II is conducted for admission to B.Arch. courses.
The JEE Main 2019 exam pattern will provide candidates with an exact idea about the marking scheme, total number of questions, the medium of question paper and other important details related to the examination. JEE Main Paper I will be conducted online i.e. in the CBT mode whereas Paper II will be conducted partly online (Mathematics and Aptitude Test) and partly offline i.e. the drawing test. The question paper of JEE Main comprises questions from the subjects of Physics, Chemistry, and Mathematics.
JEE Main Exam Pattern 2019- Highlights
Some of the important details about JEE Main exam pattern 2019 such as the marking scheme, type of questions and many more are provided in the table given below.
| Particulars | Paper I | Paper II |
| Mode of examination | Computer Based Test (CBT) mode | Online (Mathematics and Aptitude) and Offline (Drawing Test) |
| Number of sections and subjects | 3 (Physics, Chemistry and Mathematics) | 3 (Drawing, Mathematics and Aptitude) |
| Duration of entrance test | 3 hours | 3 hours |
| Number of questions | 90 questions | 82 questions |
| Type of questions | Multiple Choice Questions (MCQs) | Mathematics and Aptitude: Objective Type Questions
Drawing: Questions to check the drawing and sketching skills of candidates |
| Total Marks | 360 marks | 390 marks |
| Language of question paper | English, Hindi and Gujarati (from Gujarat, Daman & Diu and Dadra and Nagar Haveli can choose Gujarati as well) | English, Hindi and Gujarati (from Gujarat, Daman & Diu and Dadra and Nagar Haveli can choose Gujarati as well) |
| Marking Scheme of JEE Main | +4 marks are awarded for every correct answer
1 mark is deducted for every wrong answer |
+4 marks are awarded for every correct answer
1 mark is deducted for every wrong answer |
JEE Main Marking Scheme
JEE Main Marking Scheme provides students with a clear idea about the weightage of questions in the entrance examination. The marking scheme of JEE Main 2019 is provided in the table given below:
| Particulars | Paper I | Paper II |
| Correct Answer | +4 marks are awarded | +4 marks are awarded |
| Incorrect Answer | +1 mark is deducted | +1 mark is deducted |
| Un-answered question | 0 marks | 0 marks |
| Marks per section | 30 questions x 4 marks each = 120 marks per section | Mathematics: 30 questions x 4 marks each = 120 marks
Aptitude Test: 50 questions x 4 marks each = 200 marks Drawing Test = 2 questions x 35 marks each = 70 marks |
| Total Marks | 360 marks | 390 marks |
How to determine JEE Main Merit list 2019?
The method used in determining the merit list of JEE Main 2019 is provided in the table given below:
| Paper I | Paper II |
| Conversion of the marks obtained in Physics, Chemistry and Mathematics and total into the NTA mark. | Merit list for JEE Main Paper II will be prepared on the basis of candidate’s total marks in the entrance examination. |
| The final merit list will be prepared by combining the NTA scores of each shift and all days. |
Method to Resolve to Tie in JEE Main 2019
Candidates who obtain an equal score in Paper I and Paper 2 in the order mentioned below in the table:
| Paper I | Paper II |
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If the tie still persists after following the criteria mentioned above, candidates will be given the same rank.